This post is going to be one of those “occasional posts” that I talked about in the About page, which, as the reader has seen, is about the Riemann-Hurwitz formula.
I had already learnt about this formula a few years ago, and again a few weeks ago while perusing Hartshorne’s Algebraic Geometry, and came across it yet again while reading (or should I say glancing through) Diamond and Shurman’s A First Course in Modular Forms (which I call [DS] from now). I love category theory, and am not an expert at number theory – this book seemed like an interesting book, and so I borrowed it from my local library. (The only parts I fully understood were the sections on topology, charts, and Riemann surfaces.)
Now to actual math. In [DS], section 3.1, one has the Riemann-Hurwitz formula. I’m going to try to explain this from a number-theorist point of view, so please feel free to point out any mistakes.
Let and be two compact Riemann surfaces, with a nonconstant holomorphic map . The first theorem is:
Theorem: is surjective.
Proof: The image must be closed and open, thus is open, since compact sets are closed in Hausdorff spaces. Thus, is disconnected, hence a contradiction. Q.E.D.
has a number associated to it, known as the degree, a number such that for all but finitely many , which is defined by the following construction. Let denote the “multiplicity with which takes to as a map in local coordinates, making an $latex e_x$-to- map about ” ([DS]). Then, the degree is the positive integer such that for all . (For a proof of the existence of , see [DS, section 3.1].)
Let and denote the genera of $latex X$ and respectively (“genera” sounds weird, at least to me – but so does “genuses” – I guess “genii” would make sense, but that sounds a lot like the plural of “genie”…). The Riemann-Hurwitz formula is as follows:
Theorem (Riemann-Hurwitz Formula):
Proof Sketch: There’s a very interesting proof (sketch) of this theorem, as [DS] gives. First, define . Triangulate using vertices including all points of , faces and edges. Under , we may lift this to a triangulation of with edges, faces, and by ramification, vertices. Since and , the Riemann-Hurwitz formula follows.
A very detailed proof, which is in essence what I did when I expanded out the proof sketch in [DS], is here.